16y^2-40y+25=0

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Solution for 16y^2-40y+25=0 equation: 



16y^2-40y+25=0

a = 16; b = -40; c = +25;
Δ = b2-4ac
Δ = -402-4·16·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{40}{32}=1+1/4$

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